Apparently, wetted area is a major factor (assuming I did my math right).
I had to estimate some of the wetted area for the top because I couldn't get my CAD software to draw the contours I was looking for. As a substitute, I computed the area by approximation, using the areas of the triangle shapes that encompased the approximate shape I wanted.
Here's the equations and then the numbers I used:
Flat Plate Area (f), Fineness Ratio (fr) and Form Factor (FF) per the equations Tango posted
Wetted Area: 3.142(pi)*[Atop+Aside/2]
where Atop = the 2D area of the top of the drawing and Aside = the 2D area of the side. Got this equation from Raymer's book.
I iterated 6 basic sizes. All were 10 inches high and 10 inches wide of varying lengths: 3 ft long, 4 ft, 4.5 ft, 5.0 ft, 5.5 ft, 7.0 ft. The 7 foot length is approximately the length the assembly would be if the canopy was a fastback type configuration. The 10 inch height of the canopy occurs at a distance of two feet on all 6 sizes. The front and back slope away at fairly smooth contours, with the front more blunt, and back more shallow (i.e. half-teardrop shape).
3' f = 1691 in.^2
4' f = 1395 in.^2
4.5' f = 1404 in.^2
5.0' f = 1446 in.^2
5.5' f = 1461 in.^2
7' f = 1596 in.^2
Obviously the least drag is created somewhere close to 4' rather than at the longer lengths. Took me a couple hours, but interesting none-the-less. Next up is drawing the fuselage out. After that I'll put a 3D model together and post it.