is L/D direct proportional or inversely?
Inversely - more lift for less drag means you glide better (smaller angle).
Intuitively, think about it this way: Since you do not have an engine, the energy lost to drag must come at the expense of potential energy. To maintain speed the glider must keep descending, but this need is only due to energy lost on drag. Loose less = descent less.
Alternatively, you can think in terms of forces:
The drag is slowing you down, so you need some forward force to replace the thrust. By tilting the lift forward (flying at an angle downward) the lift has a component that pulls you forward on the horizontal axis.
A simple drawing of a velocity vector at an angle "a" under the horizontal, a lift perpendicular to it and drag opposite to it will show you that in order to balance the forces in the horizontal axis:
L*sin(a) = D*cos(a)
So:
L/D = 1/tan(a) or: L/D~1/a for small angles in radians. Inversely proportional to the glide angle.