Aces High Bulletin Board
General Forums => The O' Club => Topic started by: TheDudeDVant on April 30, 2004, 07:25:16 AM
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1. Grab a calculator. (You won't be able to do this
one in your head)
2. Key in the first three digits of your phone
number (NOT the area
code)
3. Multiply by 80
4. Add 1
5. Multiply by 250
6. Add the last 4 digits of your phone number
7. Add the last 4 digits of your phone number
again.
8. Subtract 250
9. Divide number by 2
Do you recognize the answer?
fun fun!
dude
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Neat! :cool:
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Umm, I don't. I've done this several times with different phone numbers. Nothing special...
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cool:cool:
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Maybe we can get curly or someone to explain it... LoL
dude
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I.E.
A = 10000 * b + c
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uh O.. a HINT!!!!!!!!!! hehe
dude
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It really a dumb joke from an algebra perspective.
Here's why.
Let's say x = first three digits of your phone say 123.
Let's say y = last four digits of your phone, say 4567.
Following all the instructions, I get an expression :
( ( (80x +1) * 250 + 2y ) -250 ) / 2
simplifying I got an equivalent expression of:
10,000x + 125 + y -125 !!!!!
So what does this tell me.
ten thousand times any numbers just adds 4 (count em 4) zeros to the original number.
so your phone number 123 now becomes 123 0000
Cute eh.
Gets better.
125 + y -125 ---- Gee the 125 is just a red herring. It cancels outs.
So now you're left with y, the last four digits of your phone,
What was that - 4567.
So its 123 0000 + 4567
yielding your phone 123- 4567.
Simple manipulation of digits.
Duh.......................... ...
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LoL Delta.. you nerd..
Hints not answers! Hints are much more fun for the masses!!
Guess the changling gets the prize today... 8)
dude