Aces High Bulletin Board
General Forums => The O' Club => Topic started by: Swoop on July 18, 2009, 02:57:57 PM
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How do I work out the r.m.s. voltage of a -52dBu microphone?
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Have you taken any readings? Once you have use the method outlined here:
http://en.wikipedia.org/wiki/Root_mean_square
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Try this link http://www.sengpielaudio.com/calculator-db-volt.htm
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Ok im curious........ Not sure I understand the question.
Is this what your looking for...
:"The degree of precision is up to you. You could measure the output with a multimeter that read directly in db..
Voltage ratio is antilog (dB/20)
On modern calculators antilog is 10^
If you entered -1 for the dB in that equation, the Voltage ratio is 0.8912509382 (just use the 0.891)
Now multiply that voltage ratio by the level you are working with....
0.891 x 1.228 = 1.094 volts RMS
Now multiply that by the peak to peak conversion = 1.094 x 2.8184 = 3.08 volts p-p.
+4dB is 1.228 x 2.8184 = 3.46 volts p-p"
Geoff'
If so go here.......follow this link http://www.auroraaudio.net/dcforum/DCForumID1/115.html (http://www.auroraaudio.net/dcforum/DCForumID1/115.html)
P.S Im not a sound expert
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Jenks, that is absolutely spot on :).
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Just curious, but why do you need the conversion?
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Mate of mine doing a degree in music theory, got completely lost on this bit and asked me for help.....like I know anything.
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College teaches you how to find out stuff :)
It's working :)
-GE