Aces High Bulletin Board
General Forums => The O' Club => Topic started by: chaser on December 25, 2011, 12:46:30 AM
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I know we have some guys on here who are great with math. I used to be better but I don't use it now that I'm not in school so I'm a bit rusty. I remember in college trig that there was a way to find how many degrees were in the arch of a circle between two points on the circle. There was a formula to figure that out.
What I'm trying to do is figure out how many degrees between two points on the earths surface. Since it's the earth I know the math won't be exact since it's not a perfect sphere. After I find this out I want to figure to draw a straight line between the two points and measure how far it is between that line on the farthest point of the arch above it. Much like this:
(http://i586.photobucket.com/albums/ss304/longhornsfan2010/IMAG0387.jpg)
I've used what math I can remember and determined x to be about 226.14 ft if the length of the straight line between those two points is 571.41 miles. As I said before this is not exactly what it is on the earth, but rather a perfect sphere. Can anyone who knows the formula check this to see if I'm even close or point me in the right direction to the formula?
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S=rθ
http://www.mathwarehouse.com/trigonometry/radians/s=r-theta-formula-equation.php
I am not checking it because screw doing math on Christmas but if you like it than Merry Christmas to you. You will have to find what the radius of the Earth is to use this but I am sure you can find that on the internet easily.
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That was exactly it! Thanks curry!
I realized this morning that I made a mistake in what I figured up last night.. s :saluteo this will help me a lot.
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Ok I'm having some trouble with this. I know I'm going to have to use trianglation to solve for x in this problem. But what I keep running into is that x is a negative number. I can find what my angle is between to two points and the arc length between them. If anyone can help me out here I would greatly appreciate it. This is not for school or anything, just something I like to do on my free time and I can't stand not finding the correct answer.
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Ok I'm having some trouble with this. I know I'm going to have to use trianglation to solve for x in this problem. But what I keep running into is that x is a negative number. I can find what my angle is between to two points and the arc length between them. If anyone can help me out here I would greatly appreciate it. This is not for school or anything, just something I like to do on my free time and I can't stand not finding the correct answer.
You've gone and done it now I am going to have to do it to because it is now bothering me.
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NERDS!!!!
(http://www.myremoteradio.com/wordpress/wp-content/uploads/2011/06/revenge-of-the-nerds.jpg)
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Of course, I kid. :)
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NERDS!!!!
(http://www.myremoteradio.com/wordpress/wp-content/uploads/2011/06/revenge-of-the-nerds.jpg)
:rofl
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lol have at it. I did manage to just now get an answer of 11.8064ft. I still don't feel like this is right though.
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Of course, I kid. :)
Wow just because I play TOR isn't it?
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lol have at it. I did manage to just now get an answer of 11.8064ft. I still don't feel like this is right though.
I almost have it give me like 2 minutes.
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NERDS!!!!
(http://www.myremoteradio.com/wordpress/wp-content/uploads/2011/06/revenge-of-the-nerds.jpg)
:rofl :rofl :rofl
Don't be hating on our smarts cause your jealous :D
Joking :devil
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Wow just because I play TOR isn't it?
Actually I do not care, I spend alot of my time flying cartoon airplanes.
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Actually I do not care, I spend alot of my time flying cartoon airplanes.
effing lols
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nevermind
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Alright here we go.
This is the hard way using good old hard math to prove that it works. The 'x' we were trying to find is actually called the sagitta.
(http://i807.photobucket.com/albums/yy355/greencurrycamo/SagittaofaCircle.jpg)
The easy way is to find the sagitta is this.
s = r - ((r^2) - (l^2))^(1/2)
http://en.wikipedia.org/wiki/Sagitta_%28geometry%29
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Alright here we go.
This is the hard way using good old hard math to prove that it works. The 'x' we were trying to find is actually called the sagitta.
(http://i807.photobucket.com/albums/yy355/greencurrycamo/SagittaofaCircle.jpg)
The easy way is to find the sagitta is this.
s = r - ((r^2) - (l^2))^(1/2)
http://en.wikipedia.org/wiki/Sagitta_%28geometry%29
Awesome! I'll have to change the numbers up and work it out a few times now! Thanks for the help curry and a big :salute to you. Merry Christmas!