Math geeks question :)

[Jackal1]

Wanna see if I have the right formula here.
OK, I`m trying to figure the liquid capacity of an upright cylindrical container in U.S. gallons.
Is LengthXWidthXliquid level /231= gallons correct?

In other words..if the container is 32 " high  32"  wide and the liquid level is to the top (32 ")  , then the capcity would be 141.852xxx gallons.
Is that correct?

[Thrawn]

pi *radius of the circle squared * height, gets you the volume.  Not sure about making it gallons.

[Nash]

Five.

[Shane]

111 gallons, approximately.

http://www.abe.msstate.edu/~fto/tools/vol/cylinder.html  use 0 for inner radius (a solid cylinder of gas so to speak)

then

http://www.abe.msstate.edu/~fto/calculator/convertv.html



short form:

How to figure out the capacity of a round (cylindrical) container
Formula:

Pi  x  rē  x  height = volume in cubic inches
volume  /  cubic inches in a gallon of liquid = percentage of gallon
percentage of gallon  x  ounces in a gallon = capacity in ounces

(3.1415927) times (Radius Squared) times (Height) = Volume
(Volume) divided by (231) = Percentage of 1 Gallon
(Percentage of 1 Gallon) times (128) = Capacity in Liquid Ounces

Remember:

Pi = 3.1415927
Cubic Inches in a Gallon of Liquid = 231
Ounces in a gallon = 128
Radius = one half the Diameter
x = times; / = divided by

Though the above may give you the total capacity, it is rare that you would fill a container all the way to the top. So you may wish to use the "filling height," instead of the total height, in your calculations.

[rpm]

My head hurts now.

[john9001]

vol of liquid will change with temp, so you have to factor that in also.

[FUNKED1]

111 gal

[Estes]

Originally posted by Shane
111 gallons, approximately.

http://www.abe.msstate.edu/~fto/tools/vol/cylinder.html  use 0 for inner radius (a solid cylinder of gas so to speak)

then

http://www.abe.msstate.edu/~fto/calculator/convertv.html



short form:

How to figure out the capacity of a round (cylindrical) container
Formula:

Pi  x  rē  x  height = volume in cubic inches
volume  /  cubic inches in a gallon of liquid = percentage of gallon
percentage of gallon  x  ounces in a gallon = capacity in ounces

(3.1415927) times (Radius Squared) times (Height) = Volume
(Volume) divided by (231) = Percentage of 1 Gallon
(Percentage of 1 Gallon) times (128) = Capacity in Liquid Ounces

Remember:

Pi = 3.1415927
Cubic Inches in a Gallon of Liquid = 231
Ounces in a gallon = 128
Radius = one half the Diameter
x = times; / = divided by

Though the above may give you the total capacity, it is rare that you would fill a container all the way to the top. So you may wish to use the "filling height," instead of the total height, in your calculations.

Shane, you are an accountant isn't that right? Jeez, I hate math. And funkypants is a teacher now.

[Shane]

yes i am, but that's not accounting.  i did stay at a holiday inn express last night and had a flash of google inspiration.


wtf is hard about using google?

[Jackal1]

Well , thanks for the input, but I had it figured right to begin with.

[http://www.stearnsonline.com/marinetank/operation.htm[/URL]

[JCLerch]

Originally posted by john9001
vol of liquid will change with temp, so you have to factor that in also.

Imagine this,

Start with a cylinder full of liquid gasoline @ -30F.  Assume the container holds 5 gallons of liquid.  

Tempature rises to +80F, liquid expands, (Hopefully excess liquid spills over board, else you will have a sealed container that is now pressurized).  In any event, Pressurized or not, the container still holds 5 gals of fuel.  If excess fuel spills overboard, the result is the weight per gallon of fuel decreases, but it is still 5 gallons of fuel.

Now if the tempature drops back to -30F, and the tank is not sealed, then you will end up with less than 5 gallons of fuel.  If the tank is sealed, you still have 5 gallons of fuel, but back to its original pressure.  

Practical application of this knowledge:

Fill your auto tank while the fuel is at its coolest tempature, thus highest density.  This of course assumes that the digital fuel pump isn't calibrating the amount of fuel dispensed based on the current tempature of the fuel.  In which case, this practical application evolves into an exercise in freezing one's extremities off.

[Thrawn]

I would never in a hundred billion million years have guessed that Shane is an accountant.

[CarbHeat]

Originally posted by JCLerch
Imagine this,

Start with a cylinder full of liquid gasoline @ -30F.  Assume the container holds 5 gallons of liquid.  

Tempature rises to +80F, liquid expands, (Hopefully excess liquid spills over board, else you will have a sealed container that is now pressurized).  In any event, Pressurized or not, the container still holds 5 gals of fuel.  If excess fuel spills overboard, the result is the weight per gallon of fuel decreases, but it is still 5 gallons of fuel.

Now if the tempature drops back to -30F, and the tank is not sealed, then you will end up with less than 5 gallons of fuel.  If the tank is sealed, you still have 5 gallons of fuel, but back to its original pressure.  

This is why commercial aircraft work in Pounds (mass rather than volume) of fuel.

[bj229r]

If one train left new york at 55 mph,and aNOTHER train left LA at 45 mph............ what Britney Spear's
IQ?

[lasersailor184]

RPM.  I seriously hope calculating volume doesn't give you a headache.