Awhile back I was flying in the MA and I came upon about 5-6 friendlies ganging up against a lone enemy.
There were other friendlies milling around watching, and one of them made a comment along the lines of :
"Wow - poor guy - that's 6 to 1 odds".
I basically thought to myself ? "6 to 1 ?!?! Try like 64 to 1 at best pal!"
Anyways, here's my reasoning:
A single fight (let's assume to the finish) has basically two outcomes. Win or Lose.
2 possible outcomes - hence 2 to 1 odds.
Using basic math, it follows that:
1 vs 2 = 2 x 2 = 4 to 1 odds
1 vs 3 = 2 x 2 x 2 = 8 to 1 odds
1 vs 4 = 2 x 2 x 2 x 2 = 16 to 1 odds
1 vs 5 = 2 x 2 x 2 x 2 x 2 = 32 to 1 odds
1 vs 6 = 2 x 2 x 2 x 2 x 2 x 2 = 64 to 1 odds
...and so on...
The above also assumes EQUAL skill, luck, advantage and aircraft. More importantly, it assumes that all the bad guys wait their turn and attack you one after the other (each attack being an isolated fight to the finish).
Given that in any good gangbang, everyone attacks at the same time, I was just wondering (given that I'm not that great at that deep-thinking-n-brain stuff), if anyone had a more realistic (and sound) way to calculate the odds of surviving a gangbang.
Shamroc