warhed quick question, some nuclear physicist just mentioned on TV a meltdown in Fukushima would be 3 times as hard as chernobyl
because of 2 main points.
1st. in Chernobyl there was a fire and big explosion, the radiation particles went up to 15km in the air spread around
whole europe. A meltdown without an explosion in Fukushima would be more intense, you would need an evacuation zone of min. 100km.
and 2nd, the Fuel rods at Fukushima are much older then Chernobyl = much much more radiation.
What do you think about this statements?
I don't even know where to begin. In Chernobyl, graphite was exposed to air after the operators kept surging power, once the graphite met air, it exploded. Nuclear fuel was carried in that explosion. There was no containment building.
In the Japanese plant, there is a very large secure structure around the reactor vessel. Even in the case of a meltdown or explosion (Containment buildings are designed to take the impact of a 747), radiation and contamination will not be released through an event. A meltdown in no way causes an explosion. It is just that, the fuel becomes so hot due to lack of coolant, it melts, essentially turning into lava. The reactor vessel would not be able to contain it, and it would flow down towards the earth. It would still have to pass through the containment building, and the foundation that rests on as well. The worst case scenario in that example would be the melted nuclear fuel coming into contact with ground water, contaminating it.
There was no chance of a nuclear explosion at Chernobyl, and no chance of one in Japan. A nuclear weapon is around 98% refined fuel, a nuclear power plant is around 0.02% refined. Nuclear fuel is not concentrated enough to explode.
People are evacuated in any natural or unnatural disaster, whether it be a tsunami, earthquake, nuclear power plant event, gas line explosion, train derailment, asteroid impact, etc.
I'm not sure where this physicist you mentioned gets the idea of there being an explosion because of the meltdown.