Mino, you are just using the numbers & formual from Shaw correct?
Because, Shaw's couple of pages is just the barest framework of whats needed to calculate relative lethality, especially if you are comparing both cannons and machine guns in the same situation.
Two critical point's that you have to consider are: 1.) Explosive Energy content of Cannon shells (Shaw's lacks this totally) and 2.) British .303's do not equal US .30's, or US 20mm's are not equal to German MG151 20mm's, which are not equal to ShVAK 20mm's, etc etc etc.
A couple of years back I did a big study into relative lethality, and its all up on my website if your interested.
Vermillion's Planes of WWII. Please note however the cannon explosive component applied to the airframe is open to debate.
For instance a .303 is quite a bit different than the US .30 machine gun. Using metric numbers the US .30 delivers 52 kiljoules (kJ) of energy in a one second burst, versus 47 kJ for the British .303. The M2 .50 cal produces 220 kJ for a one second burst.
So if the x2 20mm cannons produce Y energy (to keep discussion simple).
x4 .303's + x2 20mm's = 188+Y kJ
x2 .50's + x2 20mm's = 440+Y kJ
In other words the two .50's produce 234% of the lethality of the four .303's.
If you use the US .30 cal numbers you only get 188%, which to most people seems small, but is quite statistically significant.
I highly suggest anyone interested in this subject read Emmanuel Gustins'
WWII Fighter Gun DebateOk, I'm sure I just put about 80% of the people reading this thread to sleep with all my Engineering Babble

Sorry
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Vermillion
**MOL**, Men of Leisure
[This message has been edited by Vermillion (edited 03-15-2000).]