Originally posted by Krusty
I think y'all are ignoring SEVERAL key factors here...
Namely centripetal, centrifugal, and gravitational forces.
No matter WHAT the bank, a bomb will fly straigt out of the bomb bay due to centrifugal forces on the bomb and centripetal forces on the aircraft (due to lift generated by the wings) so nix that idea.
...
Don't change the laws of physics to suit yerselves.
No centrifugal forces act on the plane in a dive. More than that - if you point your nose at a spot on the ground and hold it there, you are producing less than 1G. The acceleration of the bomb in the direction out of the bomb bay will be:
g*cos(dive angle) = G * g
while it's acceleration forward inside the bay will be:
g*sin(dive angle) - a
where "a" is the forward acceleration of the plane.
so, the bomb will leave the bay slower and move inside more as you steepen the dive angle. The slow release of the bomb from air speed of 0 (inside the bay) to air speed of a couple hundred mph (at the bay door, and not to mention turbulance) will de-stabilize it completly and might even throw it back in.
In the famous dive bombing of the Lancs with the 7 ton earthquake bombs, the bomb was hanged right at the doorway (I vaugly remember it was partially outside) and was heavy enough not to be flung by the wind before it clears the door.
a good, clean release of a bomb is not such a trivial issue. I've seen a test film of a bomb released from an F-18 in a shallow dive (20-30 deg). The bomb released from the wing, sunk about 1 meter below the plane and started to develop a precession - this caused it to slow and be flung back and up, relative to the plane, still on the dive, and it hit the elevator of the plane.
Bozon