Hi Charge,
>Edit: From another forum:
Hm, I calculate about the same kinetic energy, but twice the chemical energy. I'm using Tony's data, 4.184 J/cal, 1.335 kcal/g for chemical energy.
>Well if you don't and calculate 151/20 power by using the correct power output of Mine with PETN what would be the result for 151/20?
Well, I've not gone into exact chemical compositions because
a) It's not easy to find out which explosive what used in which shell.
a) There is a certain uncertainty about the exact composition of each explosive.
b) Chemical energy and destructive capability are not always linear for different explosives anyway. (The improved mine shell had less than 40% more energy for 40% more destructiveness.)
I looked at blast front velocities and the like and then decided to leave it at a standard energy content since more detail was as likely to introduce new errors as to improve accuracy.
>Where did U get that 40% increase in explosive power?
For example a reproduction of WW2 weapon data in the German Waffen Revue magazine.
>Well if you don't and calculate 151/20 power by using the correct power output of Mine with PETN what would be the result for 151/20?
An inaccurate figure ;-)
But I could pretend the improved mine shell had 40% more energy (which it hadn't) to arrive at the following comparison:
MG 151/20: 2,25 MW vs. 1,71 MW (at a pure Mine shell loading)
MG 151/20: 1,59 MW vs. 1,27 MW (at 1:1:3 API/HET/Mine)
MG 151/20: 1,43 MW vs. 1,16 MW (at 1:1:2 API/HET/Mine)
Hispano II: 1,06 MW (at 1:1 API/HE)
MG 151/20: 1,15 MW vs. 0,97 MW (at 1:1:1 API/HET/Mine)
Regards,
Henning (HoHun)