Author Topic: physics question  (Read 813 times)

Offline vorticon

  • Platinum Member
  • ******
  • Posts: 7935
physics question
« on: January 05, 2005, 10:24:42 PM »
luckily not related to relativity, so i should be able to get a pretty straight answer for once...


if you taka bar of iron and a bar of aluminium and drop them, they will strike the ground at the same time. BUT if you attach them, the iron bar will always strike first. why?

Offline spitfiremkv

  • Parolee
  • Silver Member
  • ****
  • Posts: 1135
physics question
« Reply #1 on: January 05, 2005, 10:27:15 PM »
the aerodynamic drag resultant is at the joint of the 2 bars. the weight resultant is somewher eon the iron bar (iron more dense than aluminum). when you have two forces that act on a body but not at the same point, a turning moment is created.

Offline United

  • Gold Member
  • *****
  • Posts: 2536
      • http://squadronspotlight.netfirms.com
physics question
« Reply #2 on: January 05, 2005, 10:29:41 PM »
How are they attached?  If side by side, it would be because the iron is heavier than aluminum.

Its the same as taking a barbell bar and some weight and dropping it.
Once with equal distribution, and once with more weight on one side.  The heavier side will fall first.

If you drop the bars separated, gravity is the only force pushing them down.  When you combine them, you add the fact of weight distribution (not the right terminology) and inertia

I dont know the actual word for it, but its something along those lines.

Offline vorticon

  • Platinum Member
  • ******
  • Posts: 7935
physics question
« Reply #3 on: January 05, 2005, 10:34:45 PM »
k got it, basicly its a see-saw dealy, heavier side swings down and stays there. just have to forget about gravity as its non relevant to the question.

Offline spitfiremkv

  • Parolee
  • Silver Member
  • ****
  • Posts: 1135
physics question
« Reply #4 on: January 05, 2005, 10:35:40 PM »
neah it only happens in the air.

and come to think of it, the aluminum bar will fall slower than the iron bar in air!

in vacuum, the joint bar will fall straight.

Offline Lizking

  • Parolee
  • Gold Member
  • *****
  • Posts: 2502
physics question
« Reply #5 on: January 05, 2005, 10:38:59 PM »
Wrong, ladies.  The only way it will happen  that the iron lands below the aluminum, attached or not,  is if the bars are big enough for  air resistance to come into play.

Offline spitfiremkv

  • Parolee
  • Silver Member
  • ****
  • Posts: 1135
physics question
« Reply #6 on: January 05, 2005, 10:39:54 PM »
thanks for reposting what I just said :D

Offline Lizking

  • Parolee
  • Gold Member
  • *****
  • Posts: 2502
physics question
« Reply #7 on: January 05, 2005, 10:43:44 PM »
Yep, you had it right.

Offline vorticon

  • Platinum Member
  • ******
  • Posts: 7935
physics question
« Reply #8 on: January 05, 2005, 11:10:52 PM »
Quote
Originally posted by Lizking
Wrong, ladies.  The only way it will happen  that the iron lands below the aluminum, attached or not,  is if the bars are big enough for  air resistance to come into play.


they have exactly the same shape and dimension. air resistance would be about the same

Offline Pei

  • Silver Member
  • ****
  • Posts: 1903
physics question
« Reply #9 on: January 05, 2005, 11:33:34 PM »
Quote
Originally posted by vorticon
they have exactly the same shape and dimension. air resistance would be about the same


But the centre of mass  would not be in the geometric centre of the object (because the iron bar is more dense), thus the application of air resistance (mostly a feature of the geometry of the object) would create a turning moment causing the iron part of the object to end up downwards (assuming the object fell long enough to have time to turn). Of course this assumes a uniform object: if one bar was a significant different shape the turning moment might be different.

Offline JB73

  • Plutonium Member
  • *******
  • Posts: 8780
physics question
« Reply #10 on: January 06, 2005, 12:04:20 AM »
i am imagining 2 "rods" attached down the length, to make a"double rod" say each has i diameter of 1" and length of 2'

dropping so the profile looks liek 2 oo's....

dont forget to account for the air resistance, the alumium bar has less mass and the air comming up will effect it more than the more massive and "stable" iron, hence the aluminium will slow more slowlyin relation to the iron.

i am BAD at explaining it, but i was taught it, and understand the conpect, just can't verbalize it in a drunken hze.
I don't know what to put here yet.

Offline Pei

  • Silver Member
  • ****
  • Posts: 1903
physics question
« Reply #11 on: January 06, 2005, 12:12:49 AM »
Quote
Originally posted by JB73
i am imagining 2 "rods" attached down the length, to make a"double rod" say each has i diameter of 1" and length of 2'

dropping so the profile looks liek 2 oo's....

dont forget to account for the air resistance, the alumium bar has less mass and the air comming up will effect it more than the more massive and "stable" iron, hence the aluminium will slow more slowlyin relation to the iron.

i am BAD at explaining it, but i was taught it, and understand the conpect, just can't verbalize it in a drunken hze.


Physics and alcohol don't mix! Not that that stopped me at Uni........

Offline Bluedog

  • Silver Member
  • ****
  • Posts: 915
physics question
« Reply #12 on: January 06, 2005, 04:09:32 AM »
Seeing you use aluminium and iron as an example, would the pull of the Earth's magnetic field play a part in this at all?

Offline bunch

  • Parolee
  • Nickel Member
  • ***
  • Posts: 636
      • http://hitechcreations.com/forums/forumdisplay.php?&forumid=17
physics question
« Reply #13 on: January 06, 2005, 04:55:20 AM »
the two variables determining terminal velocity in an atmosphere are density & shape coefficient

Offline Ruin%20

  • Zinc Member
  • *
  • Posts: 10
it basicly have to do with drag
« Reply #14 on: January 06, 2005, 07:52:22 AM »
well if you attach a the to bars by they`re tips  then then as the new bar (which built of the two bars) accellrate on his way down horizontally will be forced by the drag to change position to a more aerodynamic state since the iron end is heavier it will be effected less by the drag force while the other end will be effected more by  it cousing the bar to spin until the iron end  pointing down in a more aerodynamic way.  
on the other hand if you just drop them separated from each other each bar will land on his own tip.