Originally posted by dtango:
TR = n (g-loading)/ velocity
(I think that is the right formula)
Sorry I must be a bit dim..if g is expressed in newtons or kgM/sec^2 and we measure v in m/sec how does that derive an expression in m (metres). looks to me that the expression returns a figure in kg/sec. Unless the velocity was expressed as an angular velocity (degrees/sec) then we get a figure returned in kgM/degree sec.
It does seem we can measure linear velocity, G and (by filming and playback) time.
From the linear velocity (if constant) and time (to complete a circle or 10 circles)we can calculate a circumference and hence a radius. This seems pretty simple maths for sustained TR tests at various velocities and g's. (choose a velocity, find the highest g at which you can sustain it in turn and measure the time per circuit... 10 circuits at 10m/sec in 1000 secs is a circumference of 1000 m and a radius of approx 160 metres)
having done that how would I determine the relationship between V, G, and TR (rate and radius) for instantanious conditions?
any ideas? is there a relation ship between sustained and instantanious figures?
Tilt