-----------Silly, but a cool math trick-----------

[Hawklore]

Don't tell me your age; you probably would tell a falsehood anyway-but
the
Sex God will know!






YOUR AGE BY SEX MATH


This is pretty neat.
DON'T CHEAT BY SCROLLING DOWN FIRST!
It takes less than a minute .
Work this out as you read ...
Be sure you don't read the bottom until you've worked it out!
This is not one of those waste of time things, it's fun.



1. First of all, pick the number of times a week that you would like to
have sex.
(more than once but less than 10)









2. Multiply this number by 2 (just to be bold)









3. Add 5












4. Multiply it by 50 -- I'll wait while you get the calculator













5. If you have already had your birthday this year add 1756 .

If you haven't, add 1755.














6. Now subtract the four digit year that you were born.










You should have a three digit number










The first digit of this was your original number
(I.e., how many times you want to have sex each week).










The next two numbers are







YOUR AGE! (Oh YES, it is!!!!!)
Cool huh.............


THIS IS THE ONLY YEAR (2006) IT WILL EVER WORK, SO SPREAD IT AROUND
WHILE IT
LASTS.

(Originally it was Chocolate but I thought that was just gay...)

[BTAirsol]

That worked wow... Impressed.

[B@tfinkV]

it made me 22, when infact i am well past half way through 23.

[Debonair]

Originally posted by Hawklore
(Originally it was Chocolate but I thought that was just gay...)

Good move then, not changing it to "1. First of all, pick the number of times a week that you would like to
have sex with a man"

[uvwpvW]

Originally posted by Hawklore
6. Now subtract the four digit year that you were born.

Hardly surprising that you can calculate your age when you use your birth year as a factor.

First give the reader a few choices to create the illusion of variables. Then make those choices insignificant by adding large numbers. Then include your year of birth in the equation. Simple.

[deSelys]

It won't work for Curval as long as he may not answer question 1 with  a double digit number.

[mentalguy]

ill have my great-grandma take it.
shes 102yo.
will it work?

[Holden McGroin]

a = b
a^2 = a*b
a^2-b^2 = a*b-b^2
(a+b)(a-b) = b(a-b)  
(a+b) = b
a+a = a
2a = a
2 = 1

[Panzzer]

It didn't work for me, I got 778 as the final result. I said 5 to the first question, while I am 28.

If I've got enough time (not likely), I'll go through it with Holden's formula...

[Skuzzy]

If you do it in binary it is pretty easy to see what is happening.

Holden, assume b = 0;  

[Mustaine]

Originally posted by Skuzzy
If you do it in binary it is pretty easy to see what is happening.

Holden, assume b = 0;  

doing math in binary.



you

are

teh

geek

[Skuzzy]

Welllllll DUH!  

[straffo]

no need to do it in bin ,Skuzzy

(a+b)(a-b) = a² - b²

and not b(a-b)

[Holden McGroin]

Originally posted by Skuzzy
If you do it in binary it is pretty easy to see what is happening.

Holden, assume b = 0;  

All you have to do is know that a=b...

The fourth step then says zero = zero

Any multiplication or division after that is bogus.