Author Topic: plane on a conveyor belt?  (Read 19864 times)

Offline eskimo2

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plane on a conveyor belt?
« Reply #135 on: January 21, 2007, 10:41:52 AM »
Quote
Originally posted by Skuzzy
Actually, the warp theory Star Trek uses is based on the actual bending or warping of space.  The bubble around the ship keeps the space constant so the ship will not disintegrate.  It is a tricky balancing act.

It works like a magnet does.  Take a magnet, place it on paper and drop some metal particles on it.  At each end of the poles of the magnet will be a greater density of metal particles.  And at the very center of the magnet everything is balanced.  All the fields counter each other.  Warp drive theory is based on the same principles.

If you can generate a force which bends/warps/compresses space in front of the ship, then use a normal drive syste, to push the ship through the compressed/warped area of space, and then release the space after the ship passes though the compressed area, it will have the effect of moving the ship great distances at sub-light speeds.

The warp factor used in Star Trek is an exponential amount of power used to bend/compress/warp space X amount.  By the time you reach Warp 10, it is therotically impossbile to bend space any further without causing space to collapse on itself and the ship.

One of the many fallacies of how Star Trek used the theories is what happens when a ship, traveling at Warp speeds, explodes.  The ships remains would be spread over billions of miles of space (depending on the warp factor) and not be localized at all.  The particles would indeed form a long cylindrical pattern though.

The overall impact of what happens to space which was warped then immedaitely returned to a non-warped state is unknown.  However, the final episodes of TNG attempted to address the potential issues with the constant warping and releasing of compressed space.  The probable theories are still being defined.

One of the things they did get right (and they actually got more right than they did wrong) was the visual effect of entering warped space.  The object would indeed appear to elongate until it disappeared from view in a matter of micro-seconds.
---

Uh, did my geek level just increase?


Some Trekkie you are Skuzzy; this is how it really works:


Offline Kurt

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plane on a conveyor belt?
« Reply #136 on: January 21, 2007, 11:02:38 AM »
Quote
Originally posted by Holden McGroin
Better grammer would be to say, "nothing else on which to spend that energy."


And Winston Churhill would respond to you
“This is the sort of bloody nonsense up with which I will not put.”

I'll stay with his team.
--Kurt
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Offline Maverick

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plane on a conveyor belt?
« Reply #137 on: January 21, 2007, 11:04:03 AM »
Quote
Originally posted by Kurt
Well, if you are 14 as everyone is guessing, its likely there won't be any active A-10's when you are flying.  The Air Force has been trying to deactivate them for 15 years.

I'll never understand why though, it is the perfect design for the role.


I have to disagree here. The Airforce just took delivery of a new varient of the A10. It is the A10C. It's the same bird with electronic enhancements to allow standoff precision munition delivery. In other words it has a laser designator in addition to standoff rocket delivery and more precise dumb bomb capability.

DMAFB just took the delivery in December and put it in the base newspaper. The expected life of the aircraft is now at least another 20 years and likely 40 unless a substitute is found.
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Offline Kurt

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plane on a conveyor belt?
« Reply #138 on: January 21, 2007, 11:08:32 AM »
Quote
Originally posted by Skuzzy

Uh, did my geek level just increase?


GAH!

I don't think it increased at all Skuzzy, what really increased (by a few thousand) is the number of people who are aware of your rather high geek level.  Or... Geek Factor.
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'A pair of jokers beats a pair of aces'

Offline hitech

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plane on a conveyor belt?
« Reply #139 on: January 21, 2007, 11:34:30 AM »
Eskimo2: Even in your theoretical case, the conveyor and wheel speed do not equal a change in force.

Visualize yourself on a pair of roller skates standing on a moving side walk like in an air port. You are motionless relative to the building holding yourself motionless by holding a rope. On the end of the rope is a scale measuring how hard you are pulling, lets say 10 lb of force.

Speed up the side walk , the scale will read 10 lb's.
Slow down the side walk, the scale will still read 10 lb's.
Take you theoretical wheels and conveyor, scale still reads 10 lb's.

Offline majic

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plane on a conveyor belt?
« Reply #140 on: January 21, 2007, 11:42:10 AM »
Quote
Originally posted by hitech
Eskimo2: Even in your theoretical case, the conveyor and wheel speed do not equal a change in force.

Visualize yourself on a pair of roller skates standing on a moving side walk like in an air port. You are motionless relative to the building holding yourself motionless by holding a rope. On the end of the rope is a scale measuring how hard you are pulling, lets say 10 lb of force.

Speed up the side walk , the scale will read 10 lb's.
Slow down the side walk, the scale will still read 10 lb's.
Take you theoretical wheels and conveyor, scale still reads 10 lb's.


I'm not so sure about that.  But then again, I only have entry level college physics.

Offline lukster

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plane on a conveyor belt?
« Reply #141 on: January 21, 2007, 12:50:42 PM »
After thinking more on the pressure area created by a very fast moving conveyor belt (one that does not magically not affect the surrounding air) I'm convinced it would create a low pressure area resulting in strong flow of air towards it's surface from above. Even if the plane did managed to lift off it would forced back down by this downdraft.

Offline hitech

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plane on a conveyor belt?
« Reply #142 on: January 21, 2007, 01:16:30 PM »
Quote

Hi Francisco,

If I properly understand your travelator, the travelator moves at
exactly the speed of the airplane, but in the opposite
direction.  This means the wheels rotate twice as fast as they would
on a normal runway and nothing else is different.  Right?

In that case, I claim the plane would take off normally except that
the wheels would be rotating twice as fast as normally.  Since the
frictional force is, as you say, f=uR, the frictional force will be
exactly the same in the two cases since v does not appear in the
equation for the frictional force.  In other words, the frictional
force is independent of the speed. In that case the forces on the
plane are exactly the same whether the travelator is operating or
not and so the plane takes off the same way in the two cases.

Did I understand your question correctly?

Best, Dick Plano, Professor of Physics emeritus, Rutgers University


mijac: Note the Frictional force is independent of speed. Power required changes with speed, but the force remains the same.

Also note: Prior to writing flight sims I was a control engineer doing conveyor systems for 10 years. Did the friction /load/power/torque calculations many times.

Offline Wes14

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plane on a conveyor belt?
« Reply #143 on: January 21, 2007, 01:16:55 PM »
How aboutwe tweak this question:D

if u put a fan/jet engine/thrust creating device infront of this said airplane while its on the treadmill,will it take off?:D
Warning! The above post may induce: nausea, confusion, headaches, explosive diarrhea, anger, vomiting, and whining. Also this post may not make any sense, or may lead to the hijack of the thread.

-Regards,
Wes14

Offline sluggish

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plane on a conveyor belt?
« Reply #144 on: January 21, 2007, 01:30:51 PM »
Quote
Originally posted by Wes14
How aboutwe tweak this question:D

if u put a fan/jet engine/thrust creating device infront of this said airplane while its on the treadmill,will it take off?:D

Absolutely.  Ever heard of a wind tunnel?

Offline Wes14

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plane on a conveyor belt?
« Reply #145 on: January 21, 2007, 02:05:34 PM »
yep:aok
Warning! The above post may induce: nausea, confusion, headaches, explosive diarrhea, anger, vomiting, and whining. Also this post may not make any sense, or may lead to the hijack of the thread.

-Regards,
Wes14

Offline eskimo2

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plane on a conveyor belt?
« Reply #146 on: January 21, 2007, 02:23:38 PM »
Quote
Originally posted by hitech
Eskimo2: Even in your theoretical case, the conveyor and wheel speed do not equal a change in force.

Visualize yourself on a pair of roller skates standing on a moving side walk like in an air port. You are motionless relative to the building holding yourself motionless by holding a rope. On the end of the rope is a scale measuring how hard you are pulling, lets say 10 lb of force.

Speed up the side walk , the scale will read 10 lb's.
Slow down the side walk, the scale will still read 10 lb's.
Take you theoretical wheels and conveyor, scale still reads 10 lb's.


Yea, I got that Hitech; that’s what I’ve been saying all along.  

What has been ignored by most of us though is that it takes energy to increase a wheel’s rpm.  When an aircraft lands, its wheels go from 0 to 100 mph in a second.  Even if the pilot greases the landing with nearly no vertical decent, the touchdown bump the get the wheels up to an outside diameter speed of 100 mph exists, and can be felt.  The amount of energy is very small compared to the inertia of the plane and the power produced by the motor, but it does slow the plane down a tad.

One time I dropped a bowling ball out of a car window; we were going 70 mph on a deserted desert highway.  The bowling ball’s speed was cut significantly within in a second or two.  Why?  Because some of the 70 mph of non-rotational inertia had to be redistributed to rotational inertia.  In fact, the formula for the rotational inertia of a sphere: 2/5 IR squared comes to mind (back from high school physics; not sure why I remember that one).  

Reconsider the hypothetical question where the wheel and treadmill can be accelerated up to infinity and still hold together, note that we are just talking about the wheel, not the plane.  In fact, imagine that we are only talking about an aircraft wheel with say a mass of 100 lbs and no aircraft, sitting on a treadmill.  Turn the treadmill on at 10 mph suddenly and the wheel will start rolling back.  It will drift back until its rpm gets up to 10 mph.  If you were holding a rope, tied to a mass-less axle through this wheel, however, you could hold it in place.  You would feel a tug at first, then once it was up to 10 mph you would feel almost nothing and could hold it in place with one finger.  

Now imagine that at the end of 1 second the treadmill is going 10 mph, at the end of 2 seconds it is up to 20 and so on.  In this situation you would feel a constant pull.  This force would be insignificant to a big aircraft engine, but to you, you would definitely feel it.  Now exaggerate the snot out of this rpm example; if the wheel and treadmill can be accelerated up to infinity very quickly and still hold together (and not burn up) we could be talking about big forces.  If this treadmill and wheel accelerated up to 1,000,000 rpm in 1 second, the rope would tear your arm off.

Offline hitech

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plane on a conveyor belt?
« Reply #147 on: January 21, 2007, 03:01:26 PM »
I agree on the moment argument. You could theoretically  create a large enough force to hold the plane.

HiTech

Offline Mini D

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plane on a conveyor belt?
« Reply #148 on: January 21, 2007, 05:05:17 PM »
Not in this situation eskimo. The wheels are rolling as a result of forward momentum of the aircraft, not the conveyer belt. The belt itself is reacting to the wheel motion, not driving it. This effect is not present. Spin the bowling ball at exactly enough rpm to achieve a matching velocity prior to droping it and it won't slow a bit. Spin it faster and it will accelerate forward when it hits.

Once again, we reach a realm where 1,000,000 isn't enough. The conveyer would have to go to infinity the instant the plane started moving as it would have to actually cancel out acceleration from an object it is isolated from via some kind of magical frictionless bearing that enables the wheel to spin just as fast as the bearing.

The fundamental disconnect on this whole thing is the impossibility of it all. Looking at the more possible scenarios, you'll see that the resistance generated at the wheel via friction is the only thing that would reduce the acceleration of the aircraft as the wheel turned faster. It would be a minimal effect. The lift of the arcraft is in no what dependant on any other aspect of the speed of the ground in relation to the wheel. Turn the belt around and the wheel's simply wouldn't spin as the aircraft took off... but the friction created at the bearing of the wheel would be non-existant causing the plane to launch a little faster.

Offline eskimo2

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« Reply #149 on: January 21, 2007, 05:38:02 PM »
MiniD,

I was the first to state that the original question is invalid and impossible.  I get it, I got it.  I still agree that the original question is invalid based on false implied assumptions.

However,

In the original question it was stated: “This conveyor has a control system that tracks the plane's wheel speed and tunes the speed of the conveyor to be exactly the same but in the opposite direction, similar to a treadmill.”  

For such a system to work, it would have to function like an automobile cruise control.  If the plane moves forward an inch the conveyor speeds up faster and faster until the plane moves back to its original position.  If the plane falls back an inch, the system backs off a bit.

If this system could accelerate the rotation of the wheels beyond anything realistic (they hold together and don’t overheat, etc.) then the system could prevent the plane from moving forward purely by the energy being loaded into the wheels.

Try this: Clamp your belt sander onto a table upside down, perfectly level, and turn it on.  Now drop a ball or wheel onto the belt.  Watch what happens.  Read my post above; hitech gets it.  I wouldn’t be surprised if no one else does.