Because you've reached the maximum blade pitch angle and the associated opposing torque the propeller can produce.
Good write up dtango.

I set out this morning to tackle this question, but after I read some of the crap I wrote:
"the airflow vector the prop sees (the prop's local angle of attack) is the resultant of the rotational component and the free stream component."I said screw it and went back to surfing the web.

Pretty sure your explanation is more intelligible than mine would have been.
I do have a question though. Is it possible that he hasn't reached the mechanical stop at all? But that instead, by increasing prop pitch (and torque load) to a high value, has increased torque load to the point where it exactly balances the engine's max output torque. Any attempt to increase prop pitch (lower rpm) will produce an increase in load beyond the engine's capability, thereby slowing the engine down, which in turn supply's less torque to the prop, which in order to maintain the desired prop rpm must reduce prop pitch, which in turn reduces the torque load on the engine, which in turn allows the engine rpm to increase, which produces more torque, which allows the prop to go to a coarser pitch, which...... ad infinitum. I think what we're seeing is a dynamic system that's stabilized.
Just a thought
(I know there's a reduction gear between engine and prop, but I've left it out for simplicity. It really doesn't play a role in the mechanical ballet I described above)