I'm down on the deck in my F4U with less than 50% fuel and ammo when a freshly spawned 109G-10 rears his ugly head and starts making high overhead runs on me. I evade, evade, evade until finally I get him were I want him. He loses e and flat turns on the deck in an atempt to get on my 6. I engage WEP and drop two notches of flap and brake left with the stall buzzer blowing in my ear. I see him directly above my conopy and I assume within two turns I should be looking at his tail in my sights. But then ping blam boom I'm dead.
Why, assuming I weight 12,000lbs (At that point I surely did not) and he was fresh from the hanger with say half fuel and ammo at 6740LBS (A full load would be 7410lbs).
His wing loading would be 6740/173.3= 38.9
My F4U would be 12,000lbs/314=38.21.
Ok thats too close to call right, wrong.
I had half fuel and ammo plus two notches of flap. So what gives? If I'm wrong then somebody explain why. But from everything I have read about the ability of the Bf-109 compaired to the Fw-190 and the P-51 the F4U should turn behind it quite easily. And the relative wing loading agree's with me as well. I am not trying to out turn a spitty here, I am fighting a bloated G-10 with Dragster tires and a blower sticking out of the hood.
Pyro, how to you calculate the sustained turn radius on these birds? I would luv to know?
Also I have seen Jekyll's web pages on this topic and it would seems to match my finding as well.
Thanks F4UDOA