Gents,
Sgt Pappy and I were discussing some lift/drag stuff via PM which led me to start some research. I stumbled upon this document:
http://ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/20050081862_2005071383.pdf on the NASA Tech Reports Server (located here:
http://ntrs.nasa.gov/search.jsp).
Anyway, I've always used the 314 ft^2 wing area from Dean for the F4U series when running aero formulas on the aircraft. However, when I added the wing, aileron, and flap area in this report, I came up with 331 ft^2 instead of 314 ft^2. The aircraft in the test is a F4U-4, and Dean doesn't note any additional wing area being added to the 4-Hog. Did Dean miss something, or am I just imagining things?
From the report:
Wing area: 276.3 ft^2
Flap area: 36.4 ft^2
Ailerons: 18.1 ft^2=330.8 ~ 331 ft^2
I tried to think about the flap assembly and how Dean may not have counted any flap area that was covered when retracted, but the only part that's covered is the radiused area around the torque tube. The actual wetted surface of the flap is always exposed, regardless of its position. Perhaps the Navy didn't figure the area correctly? Is this showing the actual area when the 3D gull-wing affect is considered instead of the 2D planform?
I'll almost be relieved to hear I haven't considered something.