You have to look at air as a fluid, and also as being in a static state. Before the air moves over the wing it is basically stationary in relation to the airplane. If you were to move a wing through water the displaced molecules would try to rejoin at their original spot after the wing passes. It's the same for air.
What you said about viewing air as a static fluid is completely correct, however that theory of lift is wrong.
If you move a wing (or indeed any object) through water, the area around and behind that object will be disturbed. If that theory were true, I can't imagine any reason why 'wake turbulence' would exist (since that the molecules most affected by the passing of the wing would be the ones that hit the wing - but if those molecules return to their original position after the wing has passed, why would any other particles further away be affected more than those two?).
You can see this by these two things (which both demonstrate that the particles don't return to their original position). On a small scale, try this: move your finger (or a streamlined object) through a tub of water. You'll notice that there will be a lot of ripples throughout the tub (and if you can be bothered to put in some ink or food colouring, than you'll see that the water gets disturbed quite a lot). On a larger scale, watch this video:
http://www.youtube.com/watch?v=uy0hgG2pkUs. As far as I can tell, that video effectively kills the equal transit time theory - since those air molecules are most definitely not returning to their original positions!
Also, this webpage has a fairly basic wing simulator, and gives a more in-depth explanation of why that theory doesn't hold up.
http://www.grc.nasa.gov/WWW/K-12/airplane/wrong1.html