Need help with MATH question?

[SKJohn]

My daughter asked me this math question today, and I couldn't come up with the right answer - HELP!  (Been way too long since high school algebra . . . )

PROBLEM:
You have TWO types of ice cream (choco and vanilla), TWO types of toppings (caramel and fudge), and THREE type of sprinkles (nuts, peppermint and chocolate chips).  Using only one of each item, how many different combinations of ice cream cones could you make?

Please show me the math used to solve - THANKS!

[Meatwad]

Can the peppermint be substituted for green mint?

[SKJohn]

Can the peppermint be substituted for green mint?

You can substitute it for anything - just keep the numbers the same

[Waldo]

 This should be of help

http://www.youtube.com/watch?v=rLprXHbn19I

[RedBull1]

I'm in 11th grade right now, learned this bs earlier in the year...or was supposed to...hell I don't remember. It has something to do with drawing a chart like

Chocolate, Caramel, Nuts                   1
Chocolate, Caramel, Peppermint          2
Chocolate, Caramel, Chocolate chips    3
Chocolate, Fudge, Nuts                     4
Chocolate, Fudge, Peppermint            5
Chocolate, Fudge, Chocolate chips      6

Vanilla, caramel, nuts                        7
Vanilla, caramel, peppermint               8
Vanilla, caramel, Chocolate Chips        9
Vanilla, fudge, nuts                          10
Vanilla, fudge, Peppermint                 11
Vanilla, fudge, chocolate chip            12



A chart like that, soooo 12 combinations if memory serves me correct?
Doesn't she have her book? Or is it due tomorrow or something? You will usually find examples and exactly how to do stuff like this in the book...


Aaaaanyway, hope this helped

 

[shotgunneeley]

Multiply across by the number of options in each set:

Two flavors x two toppings x three sprinkles
2 x 2 x 3 = 12 potential cobinations

If, for example, she were to add the options of receiving the ice cream in a cup, cone, or milkshake, then continue the process by including the fourth set of parameters.

2 x 2 x 3 x 3 = 36 potential combinations

[rogwar]

Multiply across by the number of options in each set:

Two flavors x two toppings x three sprinkles
2 x 2 x 3 = 12 potential cobinations

If, for example, she were to add the options of receiving the ice cream in a cup, cone, or milkshake, then continue the process by including the fourth set of parameters.

2 x 2 x 3 x 3 = 36 potential combinations

 

As easy as counting trees.

[RedBull1]

Multiply across by the number of options in each set:

Two flavors x two toppings x three sprinkles
2 x 2 x 3 = 12 potential cobinations

If, for example, she were to add the options of receiving the ice cream in a cup, cone, or milkshake, then continue the process by including the fourth set of parameters.

2 x 2 x 3 x 3 = 36 potential combinations

Oh yea....that too..I should remember this stuff but...naaaah 

[shotgunneeley]

As easy as counting trees.

Uh huh, Lord knows ya gotta remember as many time-savers as possible!

[Hoarach]

Just a simple question on permutations and combinations. 

Like mentioned above just multiply across.  2x2x3

[deSelys]

42, of course!

[SKJohn]

Thank you all sooooooooooo much!

It was more like  "I bet I'm smarter than you - figure this out" kind of things. 

[morfiend]

 Someone forgot half and half,half vanilla and half chocolate! So I would use 2x2x3x2.





   

[Banshee7]

42, of course!

This guy knows what he's talking about!!

#S#



Josh

[Sabre]

I have a master's degree in EE. One night my daughter was griping while doing her homework about how hard algebra was.

"Waaaa," I said, "I've forgotten more math than you'll ever know."

"So, why aren't you over here helping me, Dad?" she shot back.

I replied, "Weren't you listening? I've forgotten it." Luckily, she's not particularly accurate at throwing text books...that algebra book could have done serious damage!