Pyro, with numbers we can do lotta things.
Don't misunderstand me, I fully respect physics and your calculations are fully right.
Your calculations in metric units: 2930kg * 9.81m/s^2 * 1000m/ 34s = 845391 Watt, which are 1148 hp (roughly, don't have at the moment exact weight of 202 and conversion factor lbs/kg).
But, on the other hand, we can also consider the power to raise 2930kg up to 6000m in 5'55":
2930kg * 9.81m/s^2 * 6000m / 355s = 485802 Watt, which are 660 hp.
What's now???
From the strict physical point of view all these calculations are correct, but can we apply these formulas as they are to a climbing AC?
I'm not an aeronautical engineer, so maybe it would be wiser for me to be silent

, but I think we have to consider other factors: considering the total energy of the AC we cannot obviously ignorate the kynetic energy it has, which comes in the energy balance (Hey, I'm not making a physics lesson!!! Are just thoughts, probably fully wrong!!!

).
The above formulas calculate simply the power required to raise a weight from 0 to x meters in a given time, starting from 0 speed and 0 meters (like a lift).
But the AC is flying at a certain speed, which probably will be higher than the minimum speed imposed by maximal climb: in that case the AC will "burn" in the first part of the climb the speed excess in form of climb rate until the speed permitted by the engine power and climb rate is reached (We can think as an example of a car driving through a road wich starts to climb).
Just my 2c...
V-twin
P.S. Remember...Only 660hp needed...
