This one has me a little perplexed.
We're all familiar with German comparisons of the ability of 20mm and 30mm cannon to destroy 4-engined bombers. It's the source of the widely-quoted 4 30mm shells versus 18-22 20mm shells to shoot down a buff.
Here is one quote from such a document:
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Fuer die einzelnen Kaliber ist folgende Anzahl von Treffern erforderlich, um den Abschuss eines viermotorigen Bombers zu erzielen:
Kaliber 2 cm, Minengeschoss, Sprengladung 18 g, 18 Treffer,
Kaliber 3cm, Minengeschoss, Sprengladung 72 g, 4 Treffer
....
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What I can't figure out is whether the number for 20mm shells refers to total 20mm hits, or to Mine shells only.
Belting for the MG151/20 was 2 Mine shells out of 5, with HE/T (2.3 gms of Nitropenta) making up the remaining 3 out of 5 shells. As Tony has previously told us, the HE/T was retained because unlike the 30mm Mine shell, the 20mm Mine shell wasn't a tracer, and this was considered important.
If that 18 refers to total 20mm shells, then the total amount of HE needed was much less when shooting 20mm than when shooting 30mm, for the same effect.
For 30mm: 4x72 = 288 gm Nitropenta
For 20mm:
18 shells - 2/5 are Mine, 3/5 are HE/T
=(18 * 2/5 * 18.6) + (18 * 3/5 * 2.3)
=159 gm Nitropenta
That's a really surprising result to me. I would have expected it to be much more efficient to detonate a large amount of HE in one place, rather than spread it in many smaller explosions.
However, if 18 refers only to the Mine shells, then in reality it took 45 20mm shells on average to down a 4-engined bomber, as Mine shells were only 2 out of 5.
Now, the total amount of HE becomes:
=(18 * 18.6) + (27 * 2.3)
= roughly 397 gms Nitropenta
This is more in line with my expectations, but it does mean that the oft-quoted 18-22 20mm shells to down a heavy bomber is wrong. It took 45 shells.
Any insight into which interpretation is correct? Is Tony still around?
Thanks,
avin
[This message has been edited by avin (edited 04-08-2001).]