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in an accelerated stall one wing is making more lift than the other causing the plan to "snap-roll".
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One wing dropping before the other has nothing to do with whether or not the stall is accelerated.
Torque is probably the biggest factor for which wing drops. I tried several times with an instructor to get a Cessna 152 to roll against torque when entering a spin (which requires a stall,) and could not.
An accelerated stall is one in which the plane is pulling G's, which increases the force pulling against lift. To recover from the approach to an accelerated stall, one simply lessens the turn by not pulling so hard on the stick.
Please pardon me for being pretentious. It is a compulsion to show off as much as an obsession with using the correct terms and concepts.
Because you assume a 1g load condition. At a 0g load factor you won't stall at 2 MPH. You can stall at any speed but you can only stall at the critical AOA.
Good explanation.
Of course, at zero G, you would only momentarily be at 2 mph as you describe a parabolic arc towards Earth.
Basically, a stall turn is a turn without continuous lift from the wings.
I have never heard the term, "stall turn."
I was taught that stall plus yaw resulted in a spin. I guess rudder is still affective in a stall condition. So, one could direct the nose with the rudder, but it would be on the edge of entering a spin.