Originally posted by Crumpp
Not bad for the very first time calculating Cl's.
So now you announce that screwing up completely a very simple calculation is not bad. Well, maybe in the elementary school.
Originally posted by Crumpp
I have also said SEVERAL times that this comes from Original Documentation!! The FW-190A4 that was captured by the RAF has an aspect ratio according to them of 5.8. The Luftwaffe says the FW-190A8 had 6.01.
The RAE paper gives just a quick and dirty wing area. There was no change in the wing area from the Fw 190A-1 to Fw 190A-9 according to original german documentation.
Originally posted by Crumpp
Right now I am searching for pre-FW-190A6 Luftwaffe documentation which shows the Aspect Ratio. And of course Pre V5.
Well, I have such documentation on my table, not difficult to find.
Originally posted by Crumpp
Got a reply back on the Cl increase in a steep bank From an aeronautical engineer:
"You asked:
>> Why doesn't the lift co-efficient go up in a Steep turn?
Maybe it does, maybe it doesn't.
The yoke (and trim) give the pilot powerful control over
the coefficient of lift."
LOL Again it all depends on the control input!!!
So now you loudly announce that an aeronautical engineer told you that there is a connection between controll input and lift coefficient. That might sound earth shaking but I believe pretty much every one here allready knows that.
Originally posted by Crumpp
According to Gripens Calculations the Spitfire and FW-190 keep about the same ratio of mass to force throughout with the FW-190 pulling out ahead the higher the G's. The clear winner in that line up is the P51! It has less force acting on it and more mass. The Spitfires appears much lower but since it is a much lighter plane it does not need as much force to put the brakes on.
You can't draw anykind of conclusions on turning performance based on the total drag only. What we need to know is the relation between thrust and drag (excess power). These can be easily added to the calculation and with the excess power (positive or negative) and the mass of the plane, we can also easily calculate forward acceleration (positive or negative). As an example below are accelerations calculated for couple planes at 483 km/h at sea level. Note that flat plate areas are now calculated same way as in the Lednicer's paper (Cdwet includes Cdi and Cd=1 for flat plate) and thrust is calculated assuming 85% efficiency and 120 kp exhaust thrust:
Spitfire IX (average), 3400 kg, 1586 hp, flat plate area 6,18 sqft, e factor 0,9
0g 0,74 m/s2
1g 0,66
2g 0,41
2,99g 0
3g -0,01
4g -0,59
5g -1,34
6g -2,26
P-51B 4128 kg, 1480 hp, flat plate area 5,23 sqft, e factor 0,8
0g 0,76 m/s2
1g 0,64
2g 0,30
2,58g 0
3g -0,26
4g -1,05
5g -2,06
6g -3,31
Fw 190 (US Navy) 3940 kg, 1740ps, flat plate area 6,69, e factor 0,8
0g 0,70 m/s2
1g 0,57
2g 0,20
2,38g 0
3g -0,42
4g -1,29
5g -2,41
6g -3,77
So here we can see that the only g load where the P-51 does higher acceleration than the Spitfire is 0 g. The max continous g load at 483 km/h is that value where the acceleration is zero and at higher g loads deacceleration shows relative decrease of the speed at given g load, the Spitfire being clearly better than other two.
It should be noted that above flat plate areas give same sea level speed values as in the real world tests:
Spitfire IX 539 km/h (A&AEE average)
P-51B 560 km/h (USAAF test)
Fw 190 537 km/h (US Navy test)
Lednicer's values would have resulted over 350 mph sea level speed for all planes.
Originally posted by Crumpp
I don't beleive the spit was known for retaining E. It was a great turner and master of the spiral climb.
Just read the numbers.
Well, actually the point is to understand numbers not just read them.
gripen